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  • The spring has a spring constant k and is held compressed a distance c by a latch. When cart 1 touches cart 2, the latch is released and all the spring's energy is given to the motion of the two carts. Ignore frictional losses in the spring and to the track. (a) You want to find the velocities of the two carts after the collision, V 1 ' and V 2 ...
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  • Block 3 of mass . m 3 is added to the system, as shown below. There is no friction between block 3 and the table. (c) Indicate whether the magnitude of the acceleration of block 2 is now larger, smaller, or the same as in the original two-block system. Explain how you arrived at your answer.
  • Jun 28, 2017 · When placed in water, the ball will sink. When placed in honey, it will float. You could find some other things with some additional information. The ball placed in water will sink with increasing velocity until it reaches a “terminal velocity”; t...
  • Find the final velocity if a mass m1 moving at velocity v1 collides inelastically with a mass m2 moving at velocity v2. Since they stick together, we apply momentum conservation: m1v1 + m2v2 = (m1 + m2) v’ and solving for v’ is simple algebra.
  • Since the two balls have equal masses, they will also experience equal accelerations. In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.
  • Nov 15, 2012 · Q.78 Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m/s and 4 m/s respectively in opposite direction, collide head on. After collision A moves with a speed of 1 m/s in the same direction,
  • Nov 27, 2006 · A spring of negligible mass is compressed between two masses on a frictionless table with sloping ramps at each end. The masses are released simultaneously. The masses have the same volume, but the density of M1 is greater than that of M2. (Select G-Greater than, L-Less than, E-Equal to. If the first is G and the rest L, enter GLLLLL).
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  • If we hang a mass from a spring and measure its stretch, how can we determine the spring constant?HW K 10 14
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  • Solution for A body of m1=2 (kg), whose directions are shown in the figure, proceeds with acceleration of a=-2i (m/s2), a body of m2=6(kg), a constant speed of…
  • = m(x/H), where m is the mass when the can is full (x = H). The center of mass of the soda alone is a distance x/2 above the base of the can. Hence h M Hm x M m M m x M mx H MH mx MH mx p p / / /. 2 2 2 2 b gb g b 2 b g b g We find the lowest position of the center of mass of the can and soda by setting the derivative of h with respect to x ...
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  • Dec 14, 2017 · Two laboratory carts of equal mass are equipped with spring bumpers (Figure 3.3.4). Predict how the speeds of the carts will compare when the springs are compressed, and the two carts are allowed ...
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  • Mass mi -10.0 kg is initially held against the spring of spring constant k-100 N/m. The spring is compressed a distance x 0.45 m. When released, m is fired towards a block of mass m2-4.4 kg initially at rest at the edge of a horizontal, frictionless table of height h-0.75 m.
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  • You can imagine that the masses are resting upon and can slide upon a smooth, horizontal table. I could also have them hanging under gravity, but this would introduce a distracting complication without illustrating any further principles.
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  • They move as a unit, with a compressed spring between them, which has a negligible mass. Then the spring is released and Consider the situation where disk 1 comes to a momentary halt shortly after the spring is released. Assuming that m1 = 1.2 kg, m2 = 2.4...
  • Aug 22, 2014 · 42 C) the ratio of masses m1 and m2 as 2 3 D) the ratio of masses m1 and m2 as 3 2 23. A particle slides down a smooth inclined plane of elevation . The incline is fixed end to end in an elevator of base length l accelerating up with acceleration a0.

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spring behaves as you hang is from a ceiling in to get the spring constant k. We use Newtons second law on the mass to do this. X~ F = m~a The only forces acting on the spring are the force of the spring, and weight. Solving the equation for k gives us: Fspring ¡mg = 0 k = mg x = (:2 kg)¢(9:81 m=s2) ( 7.0 ¡ 3.0 ) cm k = 49 N=m

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  • Two bars of masses m1 and m2 connected by a non-deformed light spring rest on a horizontal plane. The coefficient of friction between the bars and the surface is equal to k. What minimum constant force has to be applied in the horizontal...
  • At t = 0, the glider is released from rest at x = −3.00 cm (that is, the spring is compressed by 3.00 cm). A block of unknown mass is attached to a spring with a spring constant of 6.50 N/m and When the block is halfway between its equilibrium position and the end point, its speed is measured...

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The acceleration of an object equals the net force acting on it divided by its mass. % Progress . MEMORY METER. This indicates how strong in your memory this concept is.

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A mass m2 = 1.5 kg rests on a horizontal table. The coefficients of friction between m2 and the table are µs =0.3 and µk = 0.25. The mass m2 is attached by strings to masses m1 = 2.5 kg and m3 = 4.5 kg as shown. Masses m1 and m3 hang freely. The system is initially held at rest.

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Two objects of equal mass hang from independent springs of unequal spring constant and oscillate up and down. A block of mass M attached to the other end of the spring oscillates with amplitude A on a frictionless, horizontal surface.

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Feb 15, 2016 · A spring of negligible mass is compressed between two masses on a frictionless table with sloping ramps at each end. The masses are released simultaneously. The masses have the same volume, but the density of M1 is less than that of M2. Select the appropriate symbol for each statement: G (Greater than), L (Less than), or E (Equal to).

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Two blocks are connected together by an ideal spring, and are free to slide on a horizontal frictionless surface. The blocks are pulled apart so that the spr...

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